NNl
jae Llar Lmas j Xlar Xmas jXar jaeLat jae Llbr Lmbs j Xlbr Xmbs jXbr jaeLb Llar Lmas Lar Llbr Lmbs Lbr
Magnetizing Circuit
FIGURE 3.114 Basic elements of a half-cycle magnetizer. The half-cycle magnetizer utilizes wound fixtures or current transformers with single-turn fixtures in conjunction with timing- and discharge-control circuitry. Duration of the applied pulse is dependent on the line frequency and adjustment of the control circuits. Pulse duration up to 8 ms may be obtained from a 60-Hz line. The magnetizing force which may be obtained is, of course, dependent on the amount of current that can be pulled off...
014
Primary and Secondary Slot Constant Calculations and k2 Note See figures for variable descriptions. k1 represents the primary stator slot constant, while k2 represents the secondary rotor slot constant. They are found using the same set of equations, being careful to use the equation which most closely resembles that of the slot in question. Round-Bottom Slot Constant k1 or k2 note that Fis different for the two constants Slot shape A see Fig. 6.29 d 3d y1 Slot shape B see Fig. 6.30...
70 100
FIGURE 2.28 Core loss versus frequency for 29G066 29 06 . FIGURE 2.28 Core loss versus frequency for 29G066 29 06 . FIGURE 2.29 Exciting power versus frequency for 29G066 29 06 100 percent parallel grain. FIGURE 2.29 Exciting power versus frequency for 29G066 29 06 100 percent parallel grain. FIGURE 2.30 Core loss versus frequency for 29G066 29 06 75 percent parallel grain and 25 percent cross grain. FIGURE 2.30 Core loss versus frequency for 29G066 29 06 75 percent parallel grain and 25...
16 Losses
Power losses generally take the form of hysteresis loss, eddy current loss, coil electrical resistance loss, and mechanical friction.The losses that are discussed here are the losses in the magnetic material, called core loss Pc, which includes the hysteresis loss PH and the eddy current loss PE. Data from U.S. Steel for the typical 60-Hz core loss in steel motor-lamination materials M19 through M45 indicates that approximately 67 percent of the core loss is due to hysteresis effects and 33...
2
Wco,air Wco, ,1 Wco, ,2 Wco, L1 Wco, L2 1.103 The total magnetic coenergy for the entire actuator is the summation of the iron and the air coenergies, as follows. Wco,tot co,iron co,air 1.104 The armature force Farm can be obtained by calculating the total actuator magnetic coenergy Wco, tot at each of two armature positions, x1 and x2. The resulting armature force is the average force over the armature position change x x1 to x2, and in the direction of the armature position change. Total...
2 1
9 gt 2 0 77 7 2 7 ln 7 1.136 Paths 96 and 97. There are additional flux paths that extend into and out of the page in Fig. 1.9. Based on the geometry shown in Fig. 1.10, there is a half-cylinder flux path 6 extending out of the page over path and into the page behind path 1, which is identical in shape to path 2. There is also a half cylindrical shell flux path 7 extending out of the page over path 6 and into the page behind path 6, which is identical in shape to path 4. The values for flux...